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vazorg [7]
3 years ago
13

How to determine whether each relation is a function {(3,-8),(-9,1),(3,2),(-4,1),(-11,-2)

Mathematics
1 answer:
crimeas [40]3 years ago
3 0
No. notice you have (3,-8) and (3,2). a function cannot have the same number on the left of the come (the x value) with different values on the right (h the y values)
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Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious
docker41 [41]

Answer:

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

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6 0
3 years ago
A rectangular pyramid is sliced so the cross section is perpendicular to its base and passes through its vertex. What is the sha
Margaret [11]
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5 0
3 years ago
Read 2 more answers
Help me please, lots of points
enot [183]
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Galina-37 [17]

Answer:

x = 4/3

Step-by-step explanation:

Direct variation:

y = kx

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The equation is

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3 years ago
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