3 years ago

How to determine whether each relation is a function {(3,-8),(-9,1),(3,2),(-4,1),(-11,-2)

1 answer:

3 0

No. notice you have (3,-8) and (3,2). a function cannot have the same number on the left of the come (the x value) with different values on the right (h the y values)

You might be interested in

Find the equation of the median from B, in ABC whose vertices are A(1, 5), B(5, 3), and

VMariaS [17]

Answer:

Step-by-step explanation:

Midpoint of AC = M(-1, 1.5)

Slope of BM = (1.5 - 3)/(-1 - 5) = ¼

Point-slope equation for line of slope ¼ that passes through B(5,3):

y-3 = ¼(x-5)

7 0

3 years ago

What is 1/10 + 50/100?

erastovalidia [21]

Answer:

$\large\boxed{\dfrac{3}{5}=0.6}$

Step-by-step explanation:

$\bold{METHOD\ 1:}\\\\\dfrac{1}{10}+\dfrac{50}{100}=\dfrac{1}{10}+\dfrac{50\!\!\!\!\diagup}{100\!\!\!\!\diagup}=\dfrac{1}{10}+\dfrac{5}{10}=\dfrac{1+5}{10}=\dfrac{6}{10}=\dfrac{6:2}{10:2}=\dfrac{3}{5}\\\\\bold{METHOD\ 2:}\\\\\text{Convert the fractions to decimal:}\\\\\dfrac{1}{10}=0.1\\\\\dfrac{50}{100}=0.50=0.5\\\\\dfrac{1}{10}+\dfrac{50}{100}=0.1+0.5=0.6$