Answer:
- a) P(x) = 32000*1.04^x
- b) $37435
- c) During year 7
Step-by-step explanation:
<u>Given</u>
- Initial pay = $32000
- Increase rate = 4%
a. <u>Formula</u>
b. Year 5 is after 4 years, so we are looking for the value of P(4)
- P(4) = $32000*1.04^4 = $37435
c. <u>P(x) = 40000, x = ?</u>
- 40000 = 32000*1.04^x
- 1.04^x = 40000/32000
- 1.04^x = 1.25
- log 1.04^x = log 1.25
- x = log 1.25 / log 1.04
- x = 5.69, this is 6 years after
The required number of the years is 6 + 1 = 7
The first thing we must do for this case is to define a variable.
We have then:
x: weight of each pallet with cement
We then have the following equation:
16x = 4856
Clearing x we have:
x = (4856) / (16)
x = 303.5 punds
Answer:
each pallet with cement weigh:
x = 303.5 punds
Answer:
f(2)=21
Step-by-step explanation:
f(2)=2^3+2*2-4+13=8+4-4+13=8+13=21
