Does 20/8 and 28/9 form a proportion

150 parents were surveyed. 26% said that the kids were noddy and 70% said their kids were nice. How many parents didn't answer w

alexandr1967 [171]

Answer:

The parents who didn't answer with either naughty and nice are 6.

Step-by-step explanation:

Given:

150 parents were surveyed. 26% said that the kids were naughty and 70% said their kids were nice.

Now, to find parents who didn't answer with either naughty and nice.

So, as given in question:

70% said that their kids are naughty.

26% said that their kids are nice.

So, to get the percentage of parents who didn't answer we subtract.

Thus, the percentage of parents who didn't answer with either naughty and nice:

100% - (70% + 26%)

100% - 96% = 4%.

Hence, 4% of parents didn't answer.

Now, to get how many parents didn't answer we calculate the percentage of the total who didn't answer:

Total parents surveyed = 150.

Parents who didn't answer = 4% of the total parents surveyed.

$Parents\ who\ didn't\ answer = 4\% of 150.$

$Parents\ who\ didn't\ answer = \frac{4}{100}\times 150.$

$Parents\ who\ didn't\ answer = \frac{600}{100}.$

$Parents\ who\ didn't\ answer = 6.$

Therefore, the parents who didn't answer with either naughty and nice are 6.

8 0

3 years ago

The mean of a certain set of measurements is 27 with a standard deviation of 14. The distribution of the

Talja [164]

Answer:

Exactly 16%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of a certain set of measurements is 27 with a standard deviation of 14.

This means that $\mu = 27, \sigma = 14$