3 years ago

Help me solve this...

Mathematics

1 answer:

klio [65]3 years ago

8 0

It is A. When you take 17.1 and subtract 3 from it, it will equal 14.1.

Hope this helped!

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g A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam. We ar

BaLLatris [955]

Answer:

The test statistic is $z = 1.25$

Step-by-step explanation:

We are interested in determining whether or not the proportion of the student who experience anxiety during the exam is significantly more than 80%.

At the null hypothesis, we test if the proportion is 80%, that is:

$H_0: p = 0.8$

At the alternate hypothesis, we test if the proportion is more than 80%, that is:

$H_a: p > 0.8$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

80% is tested at the null hypothesis:

This means that $\mu = 0.8, \sigma = \sqrt{0.2*0.8} = 0.4$

A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam.

This means that $n = 100, X = \frac{85}{100} = 0.85$

The test statistic is

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.85 - 0.8}{\frac{0.4}{\sqrt{10}}}$

$z = 1.25$

The test statistic is $z = 1.25$

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2 years ago

Marla did 65 sit ups each day for 1 week. Use the distributive property to show an expression u can use to find the total number

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<span>the total number of sit ups = 7(60 + 5)
= 7 * 60 + 7 * 5
= 420 + 35
= 455

Hope it helps</span>

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2 years ago