*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon:
square units
(22)
Similar to (21)
Area =
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:


Hence, area of the hexagon will be:
square units
(24)
Given is the inradius of an equilateral triangle.

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle =
square units
Answer:
You have to use the Pythagorean Theorem to find the other side, which will be your base in the Area formula (A=1/2bh). So the Pythagorean theorem would be 36^2 + b^2 = 60^2. This gives you 48 in for your base/missing side length. Then, you plug it into the area formula. So, A=1/2(48) (36). This gives you 864 in^2 for the area of your triangle.
Answer:
n=3
Step-by-step explanation:
Simplifying
8n + 12 + -5n = 21
Reorder the terms:
12 + 8n + -5n = 21
Combine like terms: 8n + -5n = 3n
12 + 3n = 21
Solving
12 + 3n = 21
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + 3n = 21 + -12
Combine like terms: 12 + -12 = 0
0 + 3n = 21 + -12
3n = 21 + -12
Combine like terms: 21 + -12 = 9
3n = 9
Divide each side by '3'.
n = 3
Simplifying
n = 3
Answer:
1/2
Step-by-step explanation: