Answer:ΔSRT and ΔTRP
Step-by-step explanation:
We are given that R is a point on hypotenuse SP such that the segment RT is perpendicular to PS, therefore, PR=RS as the perpendicular bisector divides the line segment in two equal halves.
Now,
In ΔSRT and ΔTRP,
PR=SR( Since RT is perpendicular bisector, it divides PS in two equal halves)
∠PRT=∠SRT=90° (RT is perpendicular bisector of PS)
RT=RT(Common)
Therefore, by SAS rule of congruency,
ΔSRT ≅ΔTRP
Hence, Option D is correct.