Round 1,627,187 to the nearest ten = 1,627,190
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
The answer to the first question is B.) The student should have subtracted the 4 first, instead of adding, because it is positive originally. And the answer to the second one is D.) Distribute the -2.
Step-by-step explanation:
Hope this helps! :)
I saw the complete problem:
complete the exercise below to decompose 930
930 = _____ tens = ____ x ____
My answer is:
930 = ninety-three tens or 93 tens = 93 x 10
