Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
Answer:
The answer is 126.
Step-by-step explanation:
If you multiply 2*9 first, you get 18. Then multiply 18 by 7. The answer will be 126. I hope this helps.
3t+12-4t-6=-4
-t=-4+6-12
-t=-10
t=10
That's your answer.
Answer: 17302
Explanation: This problem requires PEMDAS.
Step 1: Parentheses
(4+3^3) = (4+27) = 31
Step 2: Exponents
31^2 = 961
Step 3: Multiplication
3x6= 18
18x961=17298
Step 4: Addition
17298 + 4 = 17302
Answer:
X is an acute angle, which means it is less than 90*, so it is probably 45*
Step-by-step explanation:
I was confused at first but then, I’m just like, I can solve this!
