and the answer should be 18 x 27. The answers were reversed.
Step-by-step explanation:
basically you can do (6x4) + 3 = 27
and (4x4) + 2 = 18.
×2-24+12×=12-15×-1×
×2+12×+15×+1×=12+24
30×/30=36/30
×=36/30
Answer:
50
Step-by-step explanation:
7+3=10. So imma turn ten into t. 5t=5xt. So 5 times 10. 50.
Hope I helped!
solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
The probability that she won't buy either car is .10. You add the two probabilities that were previously stated and then subtract them from 1.00.
.52 + .38 = .90
1.00 - .90 = .10
