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Sliva [168]
3 years ago
14

At one store you can purchase 7 apples for $5.46. At another store, You can Get five apples $3.95. Which is the better deal?

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Answer:

The first store, the one with 7 apples for 5.46 has a better deal.

Step-by-step explanation:

To be able to more easily compare the 2 prices, we need to find the price for <u>one</u> apple at each store. To do this, we can divide the price by the number of apples in each equation.

5.46/7=.78

3.95/5=.79

.78<.79 so the first store has a better deal.

Hope this helps!

zloy xaker [14]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Simplify: 36÷(–3) + 2(27÷3 x -2).
jeka94

Answer:

-48

Step-by-step explanation:

36/-3 = -12

-12 + 2(27/3 * -2)

27/3 = 9

-12 + 2(9 * -2)

9 * -2 = -18

-12 + 2(-18)

2 * -18 = -36

-12 + -36 = -12 - 36

-48

4 0
3 years ago
Which statement is true regarding the graphed functions?
algol13

Answer:

x--5-4-3-2-1

Step-by-step explanation:

because it is x axis not y axis

8 0
2 years ago
2 - 3 (2x - 5) = 6x + 1
Nataliya [291]
2 - 3 (2x - 5) = 6x + 1
2 -6x +15 = 6x +1  distribute the -3 to (2x -5)
-6x + 17 = 6x + 1  add 2 + 15
16 = 12x add the -6x to the positive 6x and subtract the 1 from 17
1 1/3 = x divide 16/12
4 0
3 years ago
Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0
3 years ago
Let's make the most liked question in the whole website
natali 33 [55]

Answer:

the answer is 21

7 0
3 years ago
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