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34kurt
3 years ago
13

Trends have gradually changed the u.s. to a(n) _____ economy focused on making life easier for busy consumers.

Business
2 answers:
Bogdan [553]3 years ago
6 0
The answer to this question is: Service economy
In service economy, the product that provided by the companies tend not to have a physical form. Because in most cases the product took in a form of action. Examples of service companies are: Massage, psychologist, cleaning service, consultation, etc.
Alona [7]3 years ago
6 0
Service econome is the answer
You might be interested in
When you are saving or investing, the amount of expected return you receive is based on this:
shutvik [7]

It is Based on The <u>Risk</u><u> </u><u>Level</u><u>.</u><u> </u>

7 0
2 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
3 years ago
Sandhill Warehouse distributes hardback books to retail stores and extends credit terms of 2/10, n/30 to all of its customers. D
Artyom0805 [142]

Answer:

Sandhill Warehouse

Journal Entries:

June 1:

Debit Inventory Account $2,575

Credit Accounts Payable (Catlin Publishers)

To record purchase on account, terms 2/10, n/30.

June 3:

Debit Accounts Receivable (Garfunkel Bookstore) $1,300

Credit Sales $1,300

To record sales of books on account.

Debit Cost of Goods Sold $900

Credit Inventory Account $900

To record cost of books sold.

June 6:

Debit Accounts Payable (Catlin Publishers) $75

Credit Inventory Account $75

To record credit for books returned.

June 9:

Debit Accounts Payable (Catlin Publishers) $2,500

Credit Cash Discount $50

Credit Cash Account $2,450

To record payment on account.

June 15:

Debit Cash Account $1,300

Credit Accounts Receivable (Garfunkel Bookstore) $1,300

To record cash receipt on account.

June 17:

Debit Accounts Receivable (Bell Tower) $1,150

Credit Sales Account $1,150

To record books sold on account.

Debit Cost of Goods Sold $750

Credit Inventory Account $750

To record cost of books sold.

June 20:

Debit Inventory Account $900

Credit Accounts Payable (Priceless Book Publishers) $900

To record purchase on account, terms 3/15, n/30.

June 24:

Debit Cash Account $1,127

Debit Cash Discount $23

Credit Accounts Receivable (Bell Tower) $ 1,150

To record cash receipt on account.

June 26:

Debit Accounts Payable (Priceless Book Publishers) $900

Credit Cash Discount $27

Credit Cash Account $873

To record payment on account.

June 28:

Debit Accounts Receivable (General Bookstore) $1,900

Credit Sales $1,900

To record sale of books on account.

Debit Cost of Goods Sold $970

Credit Inventory Account $970

To record cost of books sold.

June 30:

Debit Sales (Returns) $130

Credit Accounts Receivable (General Bookstore) $130

To record Sales credit

Debit Inventory Account $90

Credit Cost of Goods Sold $90

To record cost of returned books.

Explanation:

1. Purchase of books on account increases inventory and Accounts Payable.

2. Sale of books on account increases Sales and Accounts Receivable.  It also reduces the Inventory Account and increases the Cost of Sales.

3. Return on Purchases reverses the entries made when goods were purchased.

4. Since Garfunkel Bookstore paid after 10 days, it could not enjoy the 2% cash discount on offer.

5. Bell Tower paid within 10 days and enjoyed the 2% cash discount.

6. Priceless Book Publishers was paid within 15 days, so the 3% cash discount applies.

7. Return on Sales reverses the entries during sales.  |t reduces Sales by a contra account called Sales Returns and the Accounts Receivable.  The inventory account is increased and the Cost of Sales is reduced.

8.  Journal entries record the daily transactions of a business as they occur.  From the general journal, postings are made to the Ledger.

5 0
3 years ago
A process produces two types of products A and B. Product A is done in batches of 1000 units. It involves a setup time of 2 hour
aleksley [76]

Answer:

Explanation:

1. Only product A is produced

40 hours= 40*60*60 = 144,000 seconds

Run time 75 seconds

Setup time 2 hours

Batches= 1000 units

Run time to produce one batch of A = 1000*75sec = 75,000 seconds

Setup time = 2 hours = 7200 seconds

Remaining seconds = 144,000 - (75,000+7200) = 61,800 seconds

Product A manufactured in 61,800 sec = 61,800/75 = 824

Total Product A manufactured are = 1824 units

2. Only product B is produced

40 hours= 40*60*60 = 144,000 seconds

Run time 45 seconds  

Setup time= 1 hour

Batches= 500 units

To produce one batch of A = 500*45sec = 22,500 seconds

Setup time = 6 hours = 6*7200 seconds= 43,200sec

Remaining seconds = 144,000-(22,500+43,200) = 78,300 seconds

Product A manufactured in 78300 sec = 1740

Total Product A manufactured are = 500+1740= 2240 units

3. A and B are produced in a mix of 25% A and 75% B?

Considering loss of 3 hours setup time, 37 hours is left to produce

A is manufactured for = 25% of 37 hours = 9.25 hours = 33300 hours

B is manufactured for = 75% of 37 hours = 27.75 hours = 99900 hours

Production of A = 33300/75 sec= 444 units

Production of B = 99900/45 sec= 2220 units

6 0
2 years ago
Read 2 more answers
During 2019, Globe Life Corporation had following transactions affecting stockholders' equity: a. Feb. 1 Repurchased 230 shares
natali 33 [55]

Answer:

The requirement of question is prepare journal entries for each of above transaction; It is assumed that par value of each share is $1

Explanation:

Feb 1.

Common Stocks  230*1                           Dr.$230

Paid in capital in excess of par 230*(22-1)  Dr.$4,830

Cash 230*22                      Cr.$5,060

b. Jul 15

Cash 130*23    Dr.$ 2,990

Common Stocks 130*1     Cr.$130

Paid in capital  in excess of par 130*(23-1) Cr.$2,860

c.Oct 1

Cash 100*21             Dr.$2,100

Common Stocks 100*1            Cr.$100

Paid in Capital in excess of par 100*(21-1) Cr.$2,000

5 0
2 years ago
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