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icang [17]
4 years ago
13

Train A & train B leave a central station at the same time. They travel at the same speed, but one in opposite directions, w

ith train a heading towards station a, and train b heading towards station b. Train a reaches station a after 3 hours, train b reaches station b after 2 1/4 hours. Station a & be are 420 miles apart. What is the rate of the train
Mathematics
1 answer:
saul85 [17]4 years ago
7 0

you can do it, man
I believe in you
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Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
3 years ago
Read 2 more answers
Drag and drop the numbers into the boxes to create an expression that is equivalent to the given expression.
slega [8]
5c + 30 because you use the distributive property 5 x c + 5 x 6
3 0
3 years ago
At a basketball​ game, a team made 54 successful shots. They were a combination of​ 1- and​ 2-point shots. The team scored 93 po
Zepler [3.9K]

Answer:

iwillanswer

Genius

4.3K answers

14.6M people helped

17 one point shots and 39 two point shots were made

Solution:

Given that,

At a basketball​ game, a team made 56 successful shots

They were a combination of​ 1- and​ 2-point shots

Let "x" be the number of 1 point shots

Then, 56 - x is the number of two point shots

The team scored 95 points in all

Therefore,

1(number of 1 point shots) + 2(number of two point shots) = 95

x + 2(56 - x) = 95

x + 112 - 2x = 95

x = 112 - 95

x = 17

Then, number of two point shots = 56 - x = 56 - 17 = 39

Thus 17 one point shots and 39 two point shots were made

8 0
3 years ago
39. The equation of a line in standard form is
Harman [31]

Answer:

Let's solve for x.

4x−2y=20

Step 1: Add 2y to both sides.

4x−2y+2y=20+2y

4x=2y+20

Step 2: Divide both sides by 4.

4x/4

=  2y+20/4

x=  1/2y+5

Answer: x=  1/2y+5

6 0
3 years ago
Which two charges have a sum of 0?
Roman55 [17]

Answer:

7-7=0 or -7+7=0

hope i helped you :)

7 0
3 years ago
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