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ira [324]
4 years ago
9

3 QUESTIONS will make brainliest plz help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Assoli18 [71]4 years ago
6 0
The answer is that they are similar triangles
Tomtit [17]4 years ago
4 0
1st picture
both triangles are similar triangles

ABC has <B = 35 and <C = 55 
DEF has <E = 35 and <F = 55

<B = <E, <C = <F and <A = <D

2nd picture
similar

3rd picture
not similar
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How do you round the answer to the nearest hundredth by doing 1062.98 * 0.092 ​
devlian [24]

Answer:

97.79

Step-by-step explanation:

1062.98 * 0.092 = 97.79416

To the nearest hundredth would be to the second 9. Since 4 is less than 5 just drop the 4 and anything after it.

3 0
4 years ago
Which of the following correctly describes a line.... A. A straight path that continues forever and has only one endpoint.
Andrej [43]
C. A straight path from one point to another.
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4 years ago
Julisa wants to find the perimeter of her bedroom that is similar to her brothers . If her brothers bedroom is 12ft long and 10f
IrinaK [193]

Answer:

The perimeter of her bedroom is 36.67 ft.

Step-by-step explanation:

Julisa's bedroom is similar to her brother's bedroom.

If the width of her bedroom is w and the length is l and her brother's room has width W and length L, then

\frac{w}{W} = \frac{l}{L} ............. (1)

Now, the dimensions of her brother's bedroom are given by 12 ft long by 10 ft wide and her bedroom has length 10 ft.

Then, from equation (1) we get,

\frac{w}{10} = \frac{10}{12}

⇒ w = 8.33 ft.

Therefore, the perimeter of her bedroom is 2(8.33 + 10) = 36.67 ft. (Approximate) (Answer)

7 0
4 years ago
The area of an 14-cm-wide rectangle is 322 cm2. What is its length?<br> The length is<br> cm.
Anika [276]

Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

<u>DIAGRAM</u> :

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Here's the required formula to find the length of rectangle :

{\longrightarrow{\pmb{\sf{A_{(Rectangle)}  = l \times b}}}}

  • A = Area
  • l = length
  • b = breadth

Substituting all the given values in the formula to find the length of rectangle :

\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)}  = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l =  \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l =  \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}

Hence, the length of rectangle is 23 cm.

\begin{gathered}\end{gathered}

<u>LEARN</u><u> </u><u>MORE</u> :

\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}

\rule{300}{2.5}

6 0
2 years ago
Read 2 more answers
Repost
lana [24]

Answer:

you told me to resolve this problem

Step-by-step explanation:

7 0
3 years ago
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