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3 years ago

1/2r -3= 3 (4-3/2r) solve for r

Mathematics

1 answer:

s2008m [1.1K]3 years ago

8 0

1/2r -3= 3 (4-3/2r) is to be solved for r.

I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.

Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:

r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r

Now expand the right side, using the distributive property of

r - 3 = 24 - 9r

Regrouping so as to combine like terms:

10r = 30

Solving for r: r = 30/10 = 3

The value of r that satisfies this equation is 3

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3 years ago

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3 years ago

Suppose a sample of 972972 tenth graders is drawn. Of the students sampled, 700700 read above the eighth grade level. Using the

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Answer:

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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For this problem, we have that:

972 students, 700 read above the eight grade level. We want the confidence interver for the proportion of those who read at or below the 8th grade level. 972 - 700 = 272, so $n = 972, \pi = \frac{272}{972} = 0.28$