Given:
Perimeter of a rectangular paper = 22 inches.
Area of the rectangular paper = 28 square inches.
To find:
The dimensions of the rectangular paper.
Solution:
Let l be the length and w be the width of the rectangular paper.
Perimeter of a rectangle is:

Perimeter of a rectangular paper is 22 inches.


...(i)
Area of a rectangle is:

Area of the rectangular paper is 28 square inches.

Using (i), we get



Splitting the middle term, we get



Using zero product property, we get


If
, then by using (i)


If
, then by using (i)


Therefore, the dimensions of the paper are either
or
.
$682.11
749.99•15% or .15=112.50
So 749.99-112.50=$637.49 and
637.49 • 7% or .07= 44.62 and
44.62+637.49=$682.11
Answer:
m<S = 68 degrees.
m<D = 112 degrees
Step-by-step explanation:
Opposite angles of a parallelogram are equal so:
4x - 4 = 3x + 14
4x - 3x = 14 + 4
x = 18.
So m < S = 4(18) - 4
= 72-4
= 68 degrees.
Angles on the same side of a parallelogram are supplementary, so
m < D = 180 - 68
= 112 degrees.