Which statement is true about the function f(x)= VX?

Adam is going to cook a turkey for 14 people and wants to allow ¾ lb of turkey for each person.

Kobotan [32]

Missing info:
Turkey Sizes:
small - 2kg - 3.9kg 
medium - 4kg - 5.4kg 
large - 5.5kg - 7.2kg 
extra large - 7.3kg - 9.2kg 

Turkey Prices: 
Small / Medium - £5.99 per kg 
Large / Extra Large - £4.99 per kg

3/4 lb x 14 persons = (3*14)/4 = 42/4 = 10.5 lbs

1 lb = 450 grams

10.5 lbs * 450grams/lb = 4,725 grams

1 kg = 1000 grams

4,725 grams * 1kg/1000 grams = 4725 kg / 1000 = 4.725 kg.

4.725 kg is under the Medium size of the Turkey.

Medium sized turkey costs £5.99 per kg.

4.725 kg * £5.99 per kg = £28.30

A turkey would cost £28.30 for 14 people.

4 0

4 years ago

What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know

xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).

⇒ P(+/S) = P(+ ∩ S)

P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

P(S)

P(+/S)* P(S) = P(+ ∩ S)

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)= P(+ ∩ S) + P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

P(H)

P(+/H)*P(H) = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= P(+ ∩ S) = 0.0095 = 0.32

P(+) 0.0293

I hope it helps!

6 0

3 years ago

Can you please help !? its due at 1:00 pm. (i will mark you brainlest) can you show work if you can?

11111nata11111 [884]

Answer:

10) 9*9*9*9 = 6561

11) 2*2*2 = 8

12) 3*3*3*3*3 = 243

13) 4*4*4 = 64

14) 6*6*6*6*6 = 7776

15) 5*5*5*5 = 625

16) 8.5*8.5*8.5 = 614.125

17) 1.3*1.3 = 1.69

18) 7*7*7*7 = 2401

Used a calculator

8 0

3 years ago

Kala purchased a prepaid phone card for $30. Long distance calls cost 9 cents a minute using this card. Kala used her card only

Romashka [77]

Answer:

The call lasted 13 minutes

Step-by-step explanation:

In this question, we are told to find the number of minutes a call lasted.

The initial amount on the card is $30 and after making a phone call just once, the balance went down to $28.83

What was used would be 30 - 28.83 = $1.17 or simply 117 cents

Now these long calls come at a cost of 9 cents per minute and we have a total of 117 cents here; the number of minutes is thus 117/9 = 13

This means Kala spent 13 minutes on the call

8 0

3 years ago

Read 2 more answers

There are 5 chemistry, 6 physics, and 7 math teachers in a school. if 3 teachers are selected randomly, find the probability tha

mrs_skeptik [129]

77.2%

To find the probably and at least on you must find the probability of none and subtract from one.

The probability of none can be found like so:

(5+6 over 5+6+7)^3 = .228

1 - .228 = .772

Hope this helps!

6 0

3 years ago