When a function intersects with the x-axis, it's y value must be 0. That means when the straight line intersects with the axis, it's at the point (4k,0), so plugging those numbers into our original equation yields:
Arif's backyard is 24 by 37 meters. He wants to put a flower garden in the middle of the backyard, leaving a strip of grass of
uniform width around the flower garden. To be happy, Arif must have 424 m squared of grass. Under these conditions what will the length and width of the garden be?
1 answer:
Answer:
Length of the flower garden = 29 meters
Width of the flower garden = 16 meters
Step-by-step explanation:
I have also attached a diagram for your convenience
Now First let us see the data we are given with:
Arif's backyard length = 37 meters
Arif's backyard Width = 24 meters
Area that should be left with grass = 424 m^2
Now lets suppose the width of the stirp of grass be "a"
According the image the area of backyard will be:
Area ABCD = 24 x 37
Area ABCD = 888 m^2
The length LM will be = (37 -2a)
The Width LO will be = (24 -2a)
Area LMNO = (37 -2a) x (24 -2a)
Area LMNO = 888 -74a -48a +4a^2
Area LMNO = 4a^2 -122a + 888
Now in order the to calculate the area of the grass strip we must subtract the area LMNO from the total area ABCD and we already know that the areas the area of grass strip should be 424 m^2
hence, A = Area ABCD - Area LMNO
424 = 888 - (4a^2 -122a + 888)
424 = 888 - 4a^2 +122a - 888
424 = -4a^2 +122a
4a^2 -122a +424=0
(We can solve this quadratic equation by breaking the middle term method)
2(2x-53)(x-4) = 0
2(2x-53) = 0
2x -53 = 0
x = 53/2
x = 26.5 (Not Possible)
x-4 = 0
x = 4
Length of the flower garden = 37 -2(4)
Length of the flower garden = 29 meters
Width of the flower garden = 24 -2(4)
Width of the flower garden = 16 meters
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