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3 years ago

How do I solve? -2x2y3 · 14x2y3

Mathematics

1 answer:

Sever21 [200]3 years ago

7 0

(-2x2y3)(14x2y3) = -28x^4y^6

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Which table represents y as a function of x

hammer [34]

B the one u already have clicked

8 0

3 years ago

What is the equation for y=3x+5

VLD [36.1K]

The graph of y = -3x+5

Step 1: Since the y - intercept is 5, plot the point (0,5).

Step 2: Since the slope is -3, move 1 unit to the right and 3 units down, so plot the point (1,2).

Step 3: Connect those points by a straight line.

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3 years ago

Does anyone know what the 5√2 (simplify radicals)?

maks197457 [2]

Answer:

5√2 is as simple as it gets

5√2 ≈ 7.071068

Step-by-step explanation:

One simplifies radical expressions by removing from under the radical any squares that might be there. 2 is a prime number, so has no square factors. The simplest form of this radical expression is the one given:

5√2

Your calculator can tell you the value of this irrational number is about ...

5√2 ≈ 7.071068

8 0

3 years ago

A red ant travels 9/8 inches in 3/4 minutes and 3 3/8 inches in 2 1/4 minutes what is the ants speed in inches per minute? What

I am Lyosha [343]

Answer:

1. 1.5 inches per minute

2. 90 inches per hour

Step-by-step explanation:

speed = $\frac{distance}{time}$

1. total distance covered = $\frac{9}{8}$ + $\frac{27}{8}$

= $\frac{9+27}{8}$

= $\frac{36}{8}$

= 4 $\frac{1}{2}$ inches

Total time taken = $\frac{3}{4}$ + $\frac{9}{4}$

= $\frac{3 +9}{4}$

= $\frac{12}{4}$

= 3 minutes

The ants average speed = $\frac{4.5}{3}$

= 1 $\frac{1}{2}$

= 1.5

The ants speed is 1 $\frac{1}{2}$ inches per minute.

2. Since;

60 minutes = 1 hour

3 minutes = x hours

x = $\frac{3}{60}$

= $\frac{1}{60}$

= 0.05 hours

Speed = $\frac{4.5}{0.05}$

= 90 inches per hour

The red ants speed is 90 inches per hour.

3 0

3 years ago

A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of

Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

$2=\frac{y2-y1}{x2-x1}$ -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$

$2=\frac{y2-y1}{3.5}$

$7=y2-y1$

$y2=y1+7$

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0

3 years ago