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ololo11 [35]
3 years ago
9

How do I solve? -2x2y3 · 14x2y3

Mathematics
1 answer:
Sever21 [200]3 years ago
7 0
(-2x2y3)(14x2y3) = -28x^4y^6
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Can you please help me.
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At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =
Papessa [141]

Answer:

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

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3 0
3 years ago
HELP!!!!!!!
igomit [66]

Substituting the data points into the model:

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2 years ago
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