Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
- is the sample proportion.
In this problem, the parameters are:
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103
I would make a table and plug in numbers for x. What ever is in | |(the bars) will always come out positive.
For example:
|-2| = 2
|4| = 4
|-3/4| = 3/4
55 over 6 as an improper fraction
The bottom part got cut off a bit, but basically, since the slope is 1/3, it’s goes up by one and goes to the right by three. Since it’s positive, both must be positive.