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3 years ago

True or false????????????

Mathematics

1 answer:

Naddika [18.5K]3 years ago

8 0

False for every rate there is only one unit rate. there is however more than 1 rates for one unit rate. for example 4/2 would have 2/1 as a unit rate but 2/1 can have 4/2 and 8/4 as rates and so on. hope this helps good luck!

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Need help 50 pts plus 30 if you get it right

SIZIF [17.4K]

42 square ft because 4 times 3 is 12 and 10 times 3 is 30. 30+12=42

7 0

2 years ago

The expressions 10/12(245b−365) and 2/3(3b+6) represent the lengths of the diagonals of parallelogram WXYZ. For what value of b

makkiz [27]

Answer:

b = 1.52

Step-by-step explanation:

Length of diagonals of a parallelogram = $\frac{10}{12}(245b - 365)$ and $\frac{2}{3}(3b+6)$

If the given parallelogram is a rectangle,

Length of the diagonals will be equal in measure,

Therefore, $\frac{10}{12}(245b - 365)=\frac{2}{3}(3b+6)$

245b - 365 = $\frac{12}{10}\times \frac{2}{3}(3b+6)$

245b - 365 = $\frac{4}{5}(3b+6)$

5(245b - 365) = 4(3b + 6)

1225b - 1825 = 12b + 24

1225b - 12b = 24 + 1825

1213b = 1849

b = $\frac{1849}{1213}$

b = 1.52

5 0

2 years ago

Eric practiced piano and guitar for a total of 8 hours this week. He practiced the piano for 1/4 of that time. How many hours di

Oduvanchick [21]

Answer:

I don’t know

Step-by-step explanation:

I said idk

5 0

3 years ago

Ms. Garcia watched 6 commercials

Aleonysh [2.5K]

Answer:

15 commercials

Step-by-step explanation:

6 commercials --> 24 minute

x commercials --> 60 minute(1 hour)

x*24 = 6*60

clear x

x = (6*60)/24

x= 15

6 0

2 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago