Question

Can some help dy/dx

Answer 1

Take the derivative of x^2 to get 2x.
Take the derivative of -2xy to get -2y +-2x$\frac{dy}{dx}$ (Everytime you take the derivative of y, you write $\frac{dy}{dx}$.
Take the derivative of -3y^2 to get -6y$\frac{dy}{dx}$.
Get the terms with $\frac{dy}{dx}$ on one side to get:

-2x$\frac{dy}{dx}$ - 6y$\frac{dy}{dx}$ = 2x - 2y

Take out the common factor of $\frac{dy}{dx}$ to get:

$\frac{dy}{dx}$[-2x - 6y] = 2x - 2y

Divide by -2x - 6y to get:

$\frac{dy}{dx}$ = $\frac{2x - 2y}{-2x - 6y}$