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3 years ago

Graph the lines y=2x-3 and y=-x+3

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

Go to desmos.com and type in these equations

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Can someone please help meee

pshichka [43]

Answer:

160

Step-by-step explanation:

Angle ABE is a 180 as ABE forms a line

so angle ABC + ANGLE CBE = 180

x + 20 = 180

x = 180-20

= 160

I hope im right!!

6 0

3 years ago

Read 2 more answers

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

This is right or wrong, please anyone

BabaBlast [244]

Wrong,

You added when you were supposed to divide.

24/30 = 0.8

7 0

3 years ago

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Select all possible values of b.

lutik1710 [3]

Answer:

B? I am confused.

Step-by-step explanation:

7 0

3 years ago

What is the max value of x and the min value of x???

LUCKY_DIMON [66]

Max value of x is infinite and min value of x is 0

7 0

3 years ago

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