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Simora [160]
4 years ago
13

using the square root property and the principle root, we can take the square root of both sides to get

Mathematics
1 answer:
Alchen [17]4 years ago
4 0
<span><span><span>x = ± 2</span></span><span><span>Then the solution is </span><span>x = ± 2</span></span><span><span>hope this helps</span></span></span>
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What is the perimeter of a trapezoid that is 9.85 15 11 9
Alenkasestr [34]
So you would add the numbers together:

9.85+15+11+9=44.85

So the perimeter is 44.85
5 0
3 years ago
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What is the answer for 3/4, 1/2, 1/3, 2/9 in fraction sequence form
maxonik [38]
If you are looking for the constant it would be 2/3
4 0
3 years ago
given the function f(x)=5(x+4)^3/2, which of the following represents its y-intercept? (1)40 (2)20 (3)4 (4)30
MissTica
<span>f(x)=5(x+4)^3/2,    let y = f(x).
</span>
<span>y =5(x+4)^3/2.  The y intercept is value of y when x = 0

y intercept =  </span><span>5(0+4)^3/2 =  5*  4^3.2 =  5*6 = 30.      Use your calculator.
 
y intercept  = 30
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3 0
4 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
3 years ago
Please help me! I’m desperate
arlik [135]

Answer:

  (a) d = 0.012v^2

  (b) 4.8 m

  (c) 25 m/s

Step-by-step explanation:

(a) Writing an equation to fit a bunch of data is often a matter of trial and error. You can often get an idea of the sort of function that is involved by graphing the data points.*

When we do that, we see the relationship is non-linear with an upward curvature. It might be described by a polynomial or exponential function.

When we try a quadratic equation, we find the fit is really quite good. The graphing calculator that does this quadratic regression analysis tells us the equation is essentially ...

  d = 0.012·v^2

__

(b) The equation predicts a depth of 4.8 m.

  d = 0.012·20^2 = 4.8

__

(c) Solving for speed, we get a speed of 25 m/s.

  7.5 = 0.012v^2

  625 = v^2 . . . . . . divide by .012

  25 = v . . . . . . . . . take the square root

_____

* The energy of a falling object is proportional to the square of its speed. If we assume that the depth of penetration into the clay is proportional to the energy absorbed, then it is not surprising to see a quadratic relationship between speed and distance. What is surprising is that this relationship would show up in middle school math problem, not a high-school physics problem.

Essentially, you have to assume the form of the equation, then find the coefficients that make it so. Working with the evenly spaced table values of 5, 10, 15 m/s can simplify the effort.

A graphing calculator or spreadsheet can do the bulk of the work once the data is entered.

7 0
4 years ago
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