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2 years ago

What value of n makes the equation true?

Mathematics

2 answers:

zhannawk [14.2K]2 years ago

5 0

To get the answer you have to add 29.4 and 13.9 and you get 43.3
It is A

photoshop1234 [79]2 years ago

3 0

Add 29.4 to 13.9 to get n by itself which gives you 43.3. the answer is A

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Find the value. Please

SIZIF [17.4K]

CosA = 12/20 which is 3/5

5 0

2 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

2 years ago

- 3x + 5y = -2<br> 2x - 2y = 1<br> Solve by elem inaction

Lyrx [107]

Answer:

x=1/4 , y=-1/4. You can confirm this by substituting the numbers in.

Step-by-step explanation:

4 0

2 years ago

The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me

faust18 [17]

Answer:

Almost 2.5% of the students spent more than $275 in a semester.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 235

Standard deviation = 20

According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?

95% of the measures are within 2 standard deviation of the mean. The other 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of those are below two standard deviations of the mean and 2.5% are more than two standard deviations above the mean.

235 + 2*20 = $275

Almost 2.5% of the students spent more than $275 in a semester.

4 0

2 years ago

I just need these questions answered, there is no requirement for any explanation! If anybody could assist, that would be great!

koban [17]

Answer:

See explanation

Step-by-step explanation:

Q9. Statement Reason

1) $\angle ABD \cong \angle CBD$ Given