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forsale [732]
3 years ago
9

Change to a mixed number 5/3how to change 5/3 into a mixed number

Mathematics
2 answers:
Jet001 [13]3 years ago
3 0

Answer:1 2/3

Step-by-step explanation:You subtract 5/3 by 3/3, then add 1 as the whole number

faltersainse [42]3 years ago
3 0

Answer: 1 and 2/5

Step-by-step explanation: To write an improper fraction as a mixed number, divide the denominator into the numerator.

So here, we have 3 divided into 5.

Image provided.

Therefore, 5/3 can be written as the mixed number 1 and 2/5.

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Step-by-step explanation:

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8 0
2 years ago
Divide the difference of 50 and 10 by the sum of 3 and 2. what expression represents the statement?
Makovka662 [10]

Answer:

(50-10) ÷ (3+2)

Step-by-step explanation:

7 0
2 years ago
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The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
Please help... How many odd perfect squares are between 5 and 211?
frez [133]

Answer:

we conclude that the total number of perfect odd squares between 5 and 211 will be: 6

Step-by-step explanation:

Let us check by taking squares

  • 3² = 9
  • 5² = 25
  • 7² = 49
  • 9² = 81
  • 11² = 121
  • 13² = 169

As taking 14² = 256 would exceed 211, and 1² = 1 is smaller than 5.

Therefore, we conclude that the total number of perfect odd squares between 5 and 211 will be: 6

8 0
2 years ago
Dracula counter vehicles in a parking lot 4 out of 16 were motorcycles if this trend continues and he counts 8 more vehicles how
Nutka1998 [239]

Answer:

32

Step-by-step explanation:

7 0
3 years ago
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