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3 years ago

If m∠P = 12, find the value of x in this figure?

Mathematics

2 answers:

Ray Of Light [21]3 years ago

7 0

X = 180 - 90 - 12 = 78° (Sum of all angles in a triangle is 180)

Answer: x = 78°

DerKrebs [107]3 years ago

7 0

Answer:

The correct option is 1. The value of x is 78.

Step-by-step explanation:

Given information: ∠P = 12, PQ is tangent to the circle O at Q.

Radius is always perpendicular to the tangent at the point of tangency. It means ∠Q is a right angle, ∠Q = 90.

According to the angle sum property of triangle, the sum of interior angles of a triangle is 180 degrees.

$\angle P+\angle Q+\angle O=180$

$12+90+x=180$

$102+x=180$

$x=180-102$

$x=78$

The value of x is 78. Therefore the correct option is 1.

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Norma had both chocolate cake and coconut cake at her birthday party. There were 32 people at the party, and 50% of them picked

Lilit [14]

Answer:

There were 40 people total at the party and we assume each had cake of one type.

So, the % of those who had chocolate is:

32/40 = .8 = 80%

Step-by-step explanation:

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3 years ago

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I wanna know the answer and steps to how to do this

Elanso [62]

Recognize that the triangle is isosceles, so the two side lengths are equal.

b = 2√2

Recognize it is a right triangle, so you can use the Pythagorean theorem to compute the length of "a".

a^2 = (2√2)^2 +(2√2)^2
a^2 = 8 +8 = 16
a = √16
a = 4

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3 years ago

1. Identify the name and label the parts of the following polynomial: -2x4+24x2-10

laiz [17]

Please write this polynomial as P(x) = -2x^4+24x^2-10, using " ^ " to denote exponentiation.

This is a fourth degree polynomial, since the highest power of x is 4. Ordinarily, a fourth degree poly would have 5 terms, but here two of the coefficients of the powers of x are zero, leaving only 3 terms.

The lead coeff. of P(x) = -2x^4+24x^2-10 is -2.

The constant terms is -10. The exponent of x here is zero (0).

The degree of the middle term is 2 (see 24x^2, above)

Would you please post your other questions separately. Thank you.

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3 years ago

"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s

statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

$P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369$

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

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4 years ago

What is the value of X?

Vikki [24]

Hello There!

The third missing length would be 68°

All sides of a triangle always add up to 180°

We take the two sides we do know, add them together and then subtract the two sides added together from 180°

3 0

3 years ago

Read 2 more answers