Find the general solution of the given differential equation. y''' − 2y'' − 4y' + 8y = 0

P(n) models the price (in dollars) of a pack of n bulbs at a certain store.

ycow [4]

Answer:

Option A.

Step-by-step explanation:

The given question is incomplete. Here is the complete question.

P(n) models the price (in dollars) of a pack of n bulbs at a certain store.

When does the price of a pack increase faster ?

n 4 10 12

P(n) 12 25 28

When does the price of a pack increase faster ?

A. Between 4 and 10 bulbs

B. Between 10 and 12 bulbs

C. The price increases at the same rat over both the intervals.

To solve this question we will find the rate of increase in the prices per pack in the given intervals.

From n = 4 to n = 10

Rate of increase in price = $\frac{25-12}{10-4}$

= $\frac{13}{6}$

= 2.166 ≈ $2.17 per pack

From n = 10 to n = 12

Rate of increase in price = $\frac{28-25}{12-10}$

= $\frac{3}{2}$

= $1.5 per pack

Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.

Option A is the answer.

8 0

2 years ago

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F(x) = 2x - 3 and f(x) = f'(x), find the value of x.

Salsk061 [2.6K]

Answer:

x=1

Step-by-step explanation:

According to your typed question,

f(x)=2x-3

Let f(x)=y

y=2x-3

Now,

Interchanging the positions of x and y

x=2y-3

x+3=2y

x+3/2=y

f'(x)=x+3/2

Then,

f(x)=f'(x)

2x-3=x+3/2

2(2x-3)=x+3

4x-3=x+3

4x-x=3+3

3x=3

x=3/3

x=1

According to your image question,

f(x)=x/2x-3

f(x)=f'(x)

Now,

Let y=f(x)

y=x/2x-3

y(2x-3)=x

2xy-3=x

2xy-x=3

x(2y-1)=3

2y-1=3x

2y=3x+1

y=3x+1/2

f'(x)=3x+1/2

Then,

f(x)=f'(x)

x/2x-3=3x+1/2

2x=6xsq+2x-9x+3

2x=6xsq+7x+3

solve for x ok

8 0

2 years ago

Classify each number according to its value.

Tems11 [23]

Answer:See below and attached

Step-by-step explanation:

Given numbers

4.2×10^-6, 2.1×10^-3, 3.1×10^-2, 3.2×10^-5, 3.5×10^-4, 5.8×10^-3, 5.2×10^-4

Greater than 3.1×10^-3

3.1×10^-2, 5.8×10^-3

Between 3.1 × 10^-3 and 4.3 × 10^-5

2.1×10 ^-3, 3.5×10^-4, 5.2×10^-4

Less than 4.3 × 10^-5

4.2×10^-6, 3.2×10^-5

Step-by-step explanation

:

6 0

1 year ago

Cory just started his first job and does not have much money saved. Each month he needs to pay his rent and make payments on his

LenKa [72]

Given that Cory does not have much money saved he will be using her regular incomes to pay his rent and car, so the most appropiate bank account is a checking account.

That will let him to deposit his incomes and make the payments with checks.

It does not make sense opening an account that pays interests because the money will be spent promptly.

Answer: option a. checking account.

8 0

3 years ago

Which equation demonstrates the additive identity property?

Bezzdna [24]

Answer:

Step-by-step explanation:

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

0o 0 = 0 0 o =

5 0

2 years ago

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