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Len [333]
3 years ago
11

For the sequence -27, -12, 3, 18, ..., the expression that defines the nth term where a1 = -27 is

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

D. -27+15 (N-1)

Step-by-step explanation:

-27, -12, 3, 18

Take the second term and subtract the first term to find the common difference

-12 - (-27)

-12+27 = 15

The common difference is +15

We are adding 15 each time

The formula for an arithmetic sequence is

an = a1+d(n-1)

an = -27 +15(n-1)

DiKsa [7]3 years ago
3 0

So the formula for an arithmetic sequence (where you're adding or subtracting by the same number each time) is a_{n} = a_{1} + d(n - 1)

In this equation:

a_{n} is the nth term

a_{1} is the first term

d is the common difference (the number you're adding or subtracting each time)

n is the number of the term (e.g. 1st term, 2nd term, 3rd term etc)


So we're given that a_{1} = -27, and we can find that d = 15 (because we add 15 each term). We just plug these values into the equation to get...

a_{n} = -27 + 15 (n - 1)

It looks like that's your answer, D. But if you needed to solve it out further, you could:


We can use the distributive property...

a_{n} = -27 + 15n - 15

Then combine like terms...

a_{n} = 15n - 42


Hope that helps! Feel free to message me if you need clarification

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To solve this problem you must apply the proccedure below:

 1. Let's call:

 x: hot dogs.
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 2. Then, you must make a system of equations, as below:

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 3. Now, you can solve the system of equation as below:

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3 years ago
The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

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