I will give you 20 points

blagie [28]

The answer would be -7 n= -7 because a negative times a negative equals a postive

5 0

3 years ago

Yao Xin puts 3/10 liters of potting soil in each pot for planting flowers. She has 5 2/3 liters of potting soil. How many pots c

Korvikt [17]

Answer:

18 8/9 pots

Step-by-step explanation:

Total potting soil = 5 2/3 liters

Potting soil per pot = 3/10 liters

How many pots can Yao Xin fill?

Number of pots Yao Xin can fill = Total potting soil / Potting soil per pot

= 5 2/3 liters ÷ 3/10 liters

= 17/3 ÷ 3/10

= 17/3 × 10/3

= (17*10) / (3*3)

= 170/9

= 18 8/9

Number of pots Yao Xin can fill = 18 8/9 pots

7 0

3 years ago

Randy has 36 tiles.

victus00 [196]

Answer:

Smallest perimeter setup is (6 by 6 rectangle)

Step-by-step explanation:

Given:

Total number of tile = 36

Find:

Smallest perimeter setup

Computation:

Perimeter = 2(a + b)

So,

Perimeter if (4 by 9 rectangle )

Perimeter if (4 by 9 rectangle ) = 2[4+9]

Perimeter if (4 by 9 rectangle ) = 2[13]

Perimeter if (4 by 9 rectangle ) = 26

Perimeter if (3 by 12 rectangle )

Perimeter if (3 by 12 rectangle ) = 2[3+12]

Perimeter if (3 by 12 rectangle ) = 2[15]

Perimeter if (3 by 12 rectangle ) = 30

Perimeter if (1 by 36 rectangle )

Perimeter if (1 by 36 rectangle ) = 2[1+36]

Perimeter if (1 by 36 rectangle ) = 2[37]

Perimeter if (1 by 36 rectangle ) = 74

Perimeter if (6 by 6 rectangle )

Perimeter if (6 by 6 rectangle ) = 2[6+6]

Perimeter if (6 by 6 rectangle ) = 2[12]

Perimeter if (6 by 6 rectangle ) = 24

So,

Smallest perimeter setup is (6 by 6 rectangle)

6 0

3 years ago

Rita will rent a car for the weekend. She can choose one of two plans. The first plan has no initial fee but costs $0.90 per mil

Artemon [7]

Let M = #miles driven

Plan 1: .50M + 70 = total cost

Plan 2 .70M = total cost

To know how far she would drive to have an equal cost for either plan just set the equations equal to each other

.70M = .50M + 70

subtract .50M from both sides

.20M = 70

M = 70/.20 = 350 miles

Check the answser:

Plan 1: .50(350) + 70 = 175 + 70 = $245

Plan 2: .7(350) = $245

they are equal so our answer checks as correct

6 0

4 years ago

Over 500 million tweets are sent per day (digital Marketing ramblings website, December 15, 2014). Assume that the number of twe

Aleksandr [31]

Answer:

(a) The probability that Bob receives no tweets during his lunch hour is 0.0002.

(b) The probability that Bob receives at least 4 tweets during his lunch hour is 0.9190.

(c) The expected number of tweets Bob receives during the first 30 minutes of his lunch hour is 3.5.

(d) The probability that Bob receives no tweets during the first 30 minutes of his lunch hour is 0.0302.

Step-by-step explanation:

Let X = number of tweets.

The random variable X follows a Poisson distribution with parameter λ = 7.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-7}(7)^{x}}{x!};\ x=0, 1, 2, 3...$

(a)

Compute the probability that Bob receives no tweets during his lunch hour as follows:

$P(X=0)=\frac{e^{-7}(7)^{0}}{0!}\\=\frac{0.000192\times1}{1} \\=0.000192\\\approx0.0002$

Thus, the probability that Bob receives no tweets during his lunch hour is 0.0002.

(b)

Compute the probability that Bob receives at least 4 tweets during his lunch hour as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-7}(7)^{0}}{0!}-\frac{e^{-7}(7)^{1}}{1!}-\frac{e^{-7}(7)^{2}}{2!} - \frac{e^{-7}(7)^{3}}{3!}\\=1-0.0002-0.0064-0.0223-0.0521\\=0.9190$

Thus, the probability that Bob receives at least 4 tweets during his lunch hour is 0.9190.

(c)

The average number of tweets in 60 minutes is 7.

Then the average number of tweets in 1 minute is, $\frac{7}{60}$ .

Hence, the average number of tweets during 30 minutes is, $\frac{7}{60}\times30=3.5$

Thus, the expected number of tweets Bob receives during the first 30 minutes of his lunch hour is 3.5.

(d)

Compute the probability that Bob receives no tweets during the first 30 minutes of his lunch hour as follows:

$P(No\ tweets) = \frac{e^{-3.5}(3.5)^{0}}{0!}=\frac{0.0302\times1}{1} =0.0302$

Thus, the probability that Bob receives no tweets during the first 30 minutes of his lunch hour is 0.0302.

3 0

4 years ago