The following algorithm adds all the entries in a square n × n array A. Analyze this algorithm where the work unit is the additi
on operation. sum = 0 for i = 1 to n do for j = 1 to n do sum = sum + A[i, j] end for end for write ("Total of all array elements is", sum)
1 answer:
Answer:
T(n)=n(n+1)/2
Explanation:
See the attached picture for detailed explanation.
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