The formula to find the period of orbit of a satellite around a planet is (T^2) = (4pi^2/ gm) r3 where r is the orbit’s mean rad
ius, M is the mass of the planet, and G is the universal gravitational constant. If you are given all the values except r, how do you rewrite the formula to solve for r?
1 answer:
See the attached graphic to see this solved for "r".
You should be very careful about stating the units for each of those variables.
time in seconds
radius in meters
mass in kilograms
G = 6.674 x 10^-11 m^3 / (kilograms * seconds²)
Also, it would be worth your while to go to this web page http://www.1728.org/kepler3a.htm
It has a calculator and other information about Kepler's Third Law.
You should be very careful about stating the units for each of those variables.
time in seconds
radius in meters
mass in kilograms
G = 6.674 x 10^-11 m^3 / (kilograms * seconds²)
Also, it would be worth your while to go to this web page http://www.1728.org/kepler3a.htm
It has a calculator and other information about Kepler's Third Law.
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Answer:
The Correct option is C ) 25
Therefore the value of x is 25 when y =40.
Step-by-step explanation:
Given:
Variable 'y' is directly proportional to the variable 'x'.
......Direct Variation
Where,
k = Constant of proportionality
To Find:
value of x = ? when y = 40
Solution:
First we need to find Constant of proportionality
When x = 20 and y = 32
Substituting the values we get
Now when k =1.6 , y = 40 then x will be
Therefore the value of x is 25 when y =40.