Answer:
The graph of the line represented by the table will not intersect the graph y= 4x + 5.
Step-by-step explanation:
y = 4x + 5
Let's take the first point of the graph x = -1, y = -1
If the point (-1, -1) passes through y = 4x + 5 then they intercept at that point
y = -1 x = -1 then -1 = 4(-1) + 5
-1 = -4 + 5
-1 = 1 does not satisfy the equation that means the two lines do not intercept at (-1,-1)
Let's take the second point of the graph x = 0, y = 3
If the point (0, 3) passes through y = 4x + 5 then they intercept at that point
y = 3 x = 0 then 3 = 4(0) + 5
3 = 5 does not satisfy the equation that means the two lines do not intercept at (0,3).
Let's take the Third point of the graph x = 1, y = 7
If the point (1,7) passes through y = 4x + 5 then they intercept at that point
y = 7 x = 1 then 7 = 4(1) + 5
7 = 4 + 5
7 = 9 does not satisfy the equation that means the two lines do not intercept at (1,7)
Let's take the last point of the graph x = 2, y = 11
If the point (2,11) passes through y = 4x + 5 then they intercept at that point
y = 11 x = 2 then 11 = 4(2) + 5
11 = 8 + 5
11 = 13 does not satisfy the equation that means the two lines do not intercept at (2,11).
So the graph of the line represented by the table will not intersect the graph y= 4x + 5.
