Find four consecutive even integers whose sum is 668
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Sum the sides of both polygons and equate.
(20)
x + 4 + x + 2 + x + 5 = 2(x + 1) + 2(x + 3) ← distribute parenthesis
3x + 11 = 2x + 2 + 2x + 6
3x + 11 = 4x + 8 ( subtract 3x from both sides )
11 = x + 8 ( subtract 8 from both sides )
3 = x
(21)
5(12x) = x + 7 + 6x + 9 + x + 10
60x = 8x + 26 ( subtract 8x from both sides )
52x = 26 ( divide both sides by 52 )
x = =