3 years ago

Find four consecutive even integers whose sum is 668

Mathematics

1 answer:

lesya692 [45]3 years ago

5 0

Answer:

x+ x+2+ x+4+ x+6 = 668

4x+12 = 668

4x = 668-12

4x = 658

x = 658/4

x = 164

x+2 = 164+2

= 166

x+4 = 164+4

= 168

x+6 = 164+6

= 170

Hope it helps u mate.....

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