A) For both sets A and B, calculating the mean, range, and quartiles are a good way of measuring the center and spread. Using standard deviation may not be the best because we do not know whether the distributions are normal or not.
b) For set A, the lowest value is 63, while the highest is 86. An estimate for the mean, based on the average of these, is 74.5. Most of the 70+ values are below 74.5, so we may guess that the mean will be above the median.
For set B, the lowest is 63, while the maximum is 95. The estimated mean would be 79. But since there are more values on the 80+ and 90+ side, the median is likely to be higher than 79.
c) For set A, the mean is 74.79, while the median is 73, therefore the mean is above the median, and the prediction in part b is correct.
Answer:
Step-by-step explanation:
X = whole number
Z = fraction numarater
Y = fraction denometer
you can do
X = X/1
Z and Y = Z/Y
X/Z = C(the new numartater)
Y/1 = Y
C/Y
The odds are 3/6. They are equal to the odds of the odd numbers.
Answer:
c/16
Step-by-step explanation:
Answer:
add 200 for each of the In
Step-by-step explanation:
10 plus 200 is 210
211 = 411
536 = 736
1406 = 1606
