Well you only need the light when it's burning low
Only miss the sun when it starts to snow
Only know you love her when you let her go
Only know you've been high when you're feeling low
Only hate the road when you're missing home
Only know you love her when you let her go
And you let her goStaring at the bottom of your glass
Hoping one day you'll make a dream last
But dreams come slow and they go so fast
You see her when you close your eyes
Maybe one day you'll understand why
Everything you touch surely dies'Cause you only need the light when it's burning low
Only miss the sun when it starts to snow
Only know you love her when you let her go
Only know you've been high when you're feeling low
Only hate the road when you're missing home
Only know<span>…</span>
1. without them you wouldn’t be able to program
2. need for job interviews
3. important to be good and make the money
4. can be adaptable
5. easy to move from a business to another
Collate means to compare something or someone
Answer:
Check the explanation
Explanation:
Generally, average access time is :
hit rate * ( cache access time ) //since data found in cache
+
miss rate * ( cache access time + time to hit memory to get data from memory) // miss occurred
In this case, parallel access is happening, so we don't need to add cache access time when
a miss occurs. Therefore, in this case the formula becomes:
avg(time) = hit rate * ( cache access time )
+
miss rate * ( time to hit memory to get data from memory)
Given,
hit rate= 0.95
miss rate = 1- hit rate = 1-0.95 = 0.05
cache access time = 15 ns
memory access time = 220 ns
Put values in formula:
avg(time) =0.95 * 15 + 0.05 * 220
=25.25 ns
Answer:
num1 = float(input("Enter first digit of number: "))
num2 = float(input("Enter second digit of number: "))
num3 = float(input("Enter third digit of number: "))
if (num1 > num2) and (num1 > num3):
largest = num1
num_sqrt = num1 ** 0.5
elif (num2 > num1) and (num2 > num3):
largest = num2
num_sqrt = num2 ** 0.5
else:
largest = num3
num_sqrt = num3 ** 0.5
print("The square root of largest digit of the three digit number is",num_sqrt)
Explanation:
num1 = float(input("Enter first digit of number: "))
num2 = float(input("Enter second digit of number: "))
num3 = float(input("Enter third digit of number: "))
if (num1 > num2) and (num1 > num3):
largest = num1
num_sqrt = num1 ** 0.5
elif (num2 > num1) and (num2 > num3):
largest = num2
num_sqrt = num2 ** 0.5
else:
largest = num3
num_sqrt = num3 ** 0.5
print("The square root of largest digit of the three digit number is",num_sqrt)