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Airida [17]
4 years ago
14

2. The two figures are similar. Identify the corresponding sides. Write the similarity statement. Justify your answer.

Mathematics
1 answer:
Anni [7]4 years ago
8 0
AC and YX are corresponding sides.
AB and YZ are corresponding sides.
BC ad ZX are corresponding sides.
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Suppose that u = < u1,u2 > and v = < v1,v2 > are vectors such that | u+v |^2 = | u |^2 + | v |^2. Prove that u and v
AveGali [126]

If u= (u1,u2,u3) andv= (v1,v2,v3), then the dot product of u and v is u·v=u1v1+u2v2+u3v3. For instance, the dot product of u=i−2j−3kandv= 2j−kisu·v= 1·0 + (−2)·2 + (−3)(−1) =−1.

Properties of the Dot Product.

Let u,v, and w be three vectors and let c be a real number. Then u·v=v·u,(u+v)·w=u·w+v·w,(cu)·v=c(u·v).

Further, u·u=|u|2.  

Thus, if u=0is the zerovector, then u·u= 0, and otherwise u·u>0.1

Orthogonality Two vectors u and v are said to be  orthogonal(perpendicular), if the angle between them is 90◦.Theorem. Two vectors u and v are orthogonal if and only if u·v= 0.

7 0
3 years ago
Solve:<br>-3x = 15 how do you solve this​
dalvyx [7]

-3x=15

Divide both sides by -3 to get + x

-3x/-3= 15/-3

Cross out -3 and -3 , divide by -3 and then becomes 1*1*x= x

x=-5

Answer: x= -5

4 0
3 years ago
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What is the best description for the histogram?
kogti [31]

Answer:

A representation of numerical or categorial data. It is similar to a bar graph

Step-by-step explanation:

6 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
Why is it not possible to draw a square that is not a parallelogram
garik1379 [7]
So a square is a parallelogram with four sides of equal length and angles of equal size. <span>In other words, all squares are parallelograms, but only some parallelograms are squares.</span>
8 0
3 years ago
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