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natka813 [3]
3 years ago
9

For a STEM competition, Julienne constructed a model rocket. The rocket can reach an average height of 545 feet. Find the differ

ences between the average heigh and the actual heights reached. Then write then as positive and negative rational numbers. Order the differences from least to greatest.
Actual heights
534.2
556.4
554.0
535.3
Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Answer: -11.4, -9, 9.7, and 10.8


Step by step explanation: You had to subtract the actual height from the average height and then order the sum of each answer from least to greatest. Hope this helped!

Olenka [21]3 years ago
6 0
535.3 is the answer because? ?????????
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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

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3 years ago
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Step-by-step explanation:

\frac{-9 +  \sqrt{9^{2} -4 * 12* 7}}{2 * 12} \\ \frac{-9 -  \sqrt{9^{2} -4 * 12* 7}}{2 *12}

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3 years ago
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Umnica [9.8K]

Answer: Funciton A is linear. Its equation is y=1.66~(x) + 0

Step-by-step explanation:

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