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RUDIKE [14]
3 years ago
12

An angle measures 88° more than the measure of a complementary angle. what is the measure of each angle?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0
Let one angle be x
Let second angle be 88+x
Sum of two complementary angles = 90°
x+ 88+ x = 90°
2x + 88 = 90
2x  = 90 - 88 = 2
x = 2/2 = 1

First angle = x = 1°
Second angle = 88 + x = 88+1 = 89°
I hope it is helpful:D
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Answer:

20

Step-by-step explanation:

Convert 80% into a decimal and multiply by 25

Convert 80% into a decimal form: 0.8

Multiply 0.8 by 25 = 0.8 x 25

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Sorry if this answer is incorrect!

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3 years ago
Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters. How long, in
Oksanka [162]

Answer:

<u>0.765 meters</u> long were the sticks when laid end to end.

Step-by-step explanation:

Given:

Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters.

Now, to find the length in meters of the sticks when laid end to end.

The lengths of the sticks are:

1st stick - 45 millimeters.

2nd stick - 32 centimeters.

3rd stick - 4 decimeters.

So, we convert the units of sticks into meters by using conversion factor:

1st stick:

1 millimeter = 0.001 meter.

45 millimeters = 0.001 × 45

45 millimeters = 0.045 meter.

2nd stick:

1 centimeter = 0.01 meter.

32 centimeters = 0.01 × 32

32 centimeters = 0.32 meter.

3rd stick:

1 decimeter = 0.1 meter.

4 decimeters = 0.1 × 4

4 decimeters = 0.4 meter.

Now, adding all the three sticks length to get the the length in meters of the sticks when laid end to end:

0.045+0.32+0.4\\\\=0.765\ meters.

Therefore, 0.765 meters long were the sticks when laid end to end.

5 0
3 years ago
A theater company made 6,000 programs for their current play. The play will have 20 performances. If they would like to have the
VashaNatasha [74]
Divide 6000 by 20
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2 years ago
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VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

​= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>

​= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>

= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.​</em>

= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹​

​Answer = 72j¹⁰k⁹

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

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