Answer:
shoulda woulda coulda been B
Step-by-step explanation:
Answer:
C. 0
Step-by-step explanation:
–4j^2 + 3j – 28 = 0
The discriminant is b^2-4ac if >0 we have 2 real solutions
=0 we have 1 real solutions
<0 we have 2 imaginary solutions
a = -4, b =3 c = -28
b^2 -4ac
(3)^2 - 4(-4)*(-28)
9 - 16(28)
9 -448
This will be negative so we have two imaginary solutions.
Therefore we have 0 real solutions
Answer:Let's assume x be the smaller number.
Given that, The greater number is 4 more than the smaller number.
So, greater number= x+4.
It's also given that, The sum of two numbers is 52. Which means sum of x and x+4 must be equa to 52. Hence,
x + (x + 4) = 52
Step-by-step explanation:
4.8 is the answer hahehehehehehe sorry jus needs to be this many characters long
