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3 years ago

In the image, point A marks the center of the circle. Which two lengths must form a ratio of 2:1?

2 answers:

6 0

Draw a diameter through the center of the circle. Any radius of this circle is 1/2 the length of the diameter. Thus, if we divide the diameter into two equal parts, we have two lengths that form the ratio 2:1, where 2 represents the diameter and 1 the radius.

salantis [7]3 years ago

4 0

Answer:

EF:AI

Step-by-step explanation:

E to F is double that of AI and it needs to be in the front since it is 2:1, not 1:2. Best of luck with the rest.

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WHICH IS NOT A LINEAR FUNCTION

Tom [10]

Answer:

OPTION C

Step-by-step explanation:

IN OPT. A- 2 IS MULTIPLED IN EACH NO.

IN OPT.B-2 IS MULTIPLED

IN OPT.D-1 IS ADDED

IN OPT.E-2 IS ADDED

4 0

3 years ago

-a-10 = 5a +8 pleasee help me

professor190 [17]

Answer:

a=-3

Step-by-step explanation:

5a+a=-10-8

6a=-18

a=-18/6

a=-3

4 0

2 years ago

Read 2 more answers

There are 219 people at the science camp. 112 people are enrolled in the chemistry class, and 45 people are enrolled in the phys

eimsori [14]

Answer:

The correct answer is - 17.

Step-by-step explanation:

Given:

total students = 219

in chemistry = 112

in physics = 45

not enrolled in either of these = 79

solution:

The number of students in both classes can be calculated by

P ( A or B) = P (A) + P (B) - P (A and B)

then putting and solving the given vaues in formula

=> (219-79) = 112+45-x

=> 140 = 157 -x

=> 17 = x

6 0

3 years ago

Find the slope of the curve below at the given points. Sketch the curve along with its tangents at these points. R = sin 2 theta

mr Goodwill [35]

Answer:

<u> </u><u>-1 </u>

Step-by-step explanation:

Given that:

r = sin 2θ , θ = ± π/4 , ± 3π/4

Recall that:

x = r cosθ

y = r sinθ

The differential of y with respect to x

$\dfrac{dy}{dx} = \dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}}$

$\dfrac{dy}{dx} =\dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}} = \dfrac{ r cos \theta + sin \theta* \dfrac{dr}{d \theta} } {\dfrac{dr}{d \theta} *cos \theta- sin \theta \ r}$

at θ = π/4 , r = sin π/2

r = 1

$\dfrac{dy}{dx} = \dfrac{ r cos \theta + 2 cos (2 \theta)*sin \ \theta } {2 \ cos (2 \theta) *cos \theta- sin 2 \theta * sin \theta}$

where;

θ = π/4

$\dfrac{dy}{dx} = \dfrac{ 1 \times cos (\dfrac{\pi}{4}) + 2 cos (\dfrac{\pi}{2})*sin (\dfrac{\pi}{4}) } {2 \ cos (\dfrac{\pi}{2})*cos (\dfrac{\pi}{4})- sin (\dfrac{\pi}{2}) * sin (\dfrac{\pi}{4})}$