Because you're trying to make them congruent, equal the two expressions to each other.

So, for #10 you would equal them so it would look like this.
2x+2=5x-19

Then you would just go ahead and simplify

2x+2=5x-19
-2x -2x
---------------
2= 3x -19
+19 +19
---------------
21=3x
--- ----
3 3

x=7

This means that x should be 7. You can check this just by plugging it in

2x+2
2(7)+2 = 16

5x-19
5(7)-19= 16

Same with #11.

x+8=3x-14
-x -x
--------------
8=2x-14
+14 +14
--------------
22=2x
--- ----
2 2

x=11

Check.

x+8
11+8= 19

3x-14
3(11) - 14 = 19

6 0

3 years ago

Please answer the question please

Natali5045456 [20]

The answer to ur problem is 1/3.

3 0

4 years ago

a machine packs boxes at a constant rate of 2/3 of a box every 1/2 minute what is the number of boxes per minute that mahine pac

mote1985 [20]

Answer:

3/5

Step-by-step explanation:

8 0

3 years ago

Im doing my math homework and this question came up, and i dont know what to do. Can someone please help?

LUCKY_DIMON [66]

Data:
P = 5.300,00
A = 7.000,00
r = 9% = 0,09
n = 4
t = ?

We have the following compound interest formula:

$A = P*(1+ \frac{r}{n})^{nt}$
$7000 = 5300*(1+ \frac{0.09}{4})^{4t}$
$7000 = 5300*(1+ 0.0225)^{4t}$
$7000 = 5300*(1.0225)^{4t}$
$(1.0225)^{4t} = \frac{7000}{5300}$
$(1.0225)^{4t} = 1.32075$
Now, take the natural logarithm of both sides:
$ln(1.0225^{4t}) = ln(1.32075)$
$4*t*ln(1.0225) = = ln(1.32075)$
$4*t = \frac{ln(1.32075)}{ln(1.0225)}$
$4t = 12.50301769...$
$4t \approx 12.50302$
$t \approx \frac{12.50302}{4}$
$\boxed{t \approx 3.1258years}$

<span>Therefore, we have: (answer)
</span>
3 years 1 month and 16 days

3 0

3 years ago