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3 years ago

Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)2 = 225y2+12x3y+0.16x6

Mathematics

1 answer:

kobusy [5.1K]3 years ago

6 0

Answer:

∗ = 0.4x³

Step-by-step explanation:

(15y + ∗)² = 225y²+12x³y+0.16x⁶

Note:

225y² = 15y * 15y = (15y)²

12x³y = 2 * 15y * 0.4x³

0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²

So, by factoring the right hand side:

225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²

By comparing the left hand side with (15y + 0.4x³)²

So, ∗ should be replaced with the monomial 0.4x³

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Answer:

b = -³¹⁄₃

Step-by-step explanation:

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3 years ago

What is the reflection image of P(0, 0) after two reflections, first across x = 4 and then across y = -3?

jek_recluse [69]

Answer:

The reflection image of P(0, 0) after two reflections is (8,-6)

Step-by-step explanation:

step 1

Find the coordinates of point P after reflection across x=4

we know that

The distance from point P to the line x=4 is equal to 4 units

(0,0) -----> (4+4,0) ----> (8,0)

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The distance from point (8,0) to the line y=-3 is equal to 3 units

(8,0) -----> (8,-3-3) ----> (8,-6)

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3 years ago

The pyramid below has a square base.

zavuch27 [327]

The volume of the pyramid would be 2406.16 cubic cm.

<h3>How to find the volume of a square-based right pyramid?</h3>

Supposing that:

The length of the sides of the square base of the pyramid has = b units

The height of the considered square-based pyramid = h units,

The pyramid below has a square base.

h = 24.4 cm

b = 17.2 cm

Then, its volume is given by:

$V = \dfrac{1}{3} \times b^2 \times h \: \rm unit^3$

$V = \dfrac{1}{3} \times 17.2^2 \times 24.4 \: \rm unit^3\\\\V = 2406.16$

Therefore, the volume of the pyramid would be 2406.16 cubic cm.

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2 years ago

Solve each problem. Explain or show your reasoning.

Rufina [12.5K]

1: 40 2: 78 3: 48 4: 26 5: 15 6: 70

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3 years ago

Simplify: (–2x+y)(-58 y) O 10x10, 10xv2 10xy 10x10 ,

alekssr [168]

Answer:

Choice C

Step-by-step explanation:

$(-2x^2y)(-5x^5y^3)=\\\\(-2)(-5)\times (x^2)(x^5)\times (y)(y^3)=\\\\10x^7y^4$

Hope this helps!

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3 years ago