Answer:
![5x-y=20](https://tex.z-dn.net/?f=5x-y%3D20)
Step-by-step explanation:
We are asked to find the standard form of the equation of line, which passes through point R(4,0) and having a slope of 5.
First of all, we will write equation of line in point-slope form:
, where,
m=slope of line,
= Coordinates of point that lies on the line.
Upon substituting our given values in point-slope form of equation we will get,
![(y-0)=5(x-4)](https://tex.z-dn.net/?f=%28y-0%29%3D5%28x-4%29)
Now, we will convert our equation into standard form of equation:![ax+by=c](https://tex.z-dn.net/?f=ax%2Bby%3Dc)
Upon using distributive property we will get,
![y=5x-20](https://tex.z-dn.net/?f=y%3D5x-20)
Now we will subtract 5x from both sides of our equation as:
![-5x+y=5x-5x-20](https://tex.z-dn.net/?f=-5x%2By%3D5x-5x-20)
![-5x+y=-20](https://tex.z-dn.net/?f=-5x%2By%3D-20)
Upon multiplying our equation by -1, we will get,
![5x-y=20](https://tex.z-dn.net/?f=5x-y%3D20)
Therefore, our required equation would be
.