Question

Indicate in standard form the equation of the line passing through the given point and having the given slope. R(4, 0), m = 5

Answer 1

5x + -1y = 20
You can simplify it to 5x-y=20

Answer 2

Answer:

$5x-y=20$

Step-by-step explanation:  

We are asked to find the standard form of the equation of line, which passes through point R(4,0) and having a slope of 5.

First of all, we will write equation of line in point-slope form:

$(y-y_1)=m(x-x_1)$, where,

m=slope of line,

$(x_1,y_1)$ = Coordinates of point that lies on the line.

Upon substituting our given values in point-slope form of equation we will get,

$(y-0)=5(x-4)$

Now, we will convert our equation into standard form of equation:$ax+by=c$

Upon using distributive property we will get,

$y=5x-20$

Now we will subtract 5x from both sides of our equation as:

$-5x+y=5x-5x-20$

$-5x+y=-20$

Upon multiplying our equation by -1, we will get,

$5x-y=20$

Therefore, our required equation would be $5x-y=20$.