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vodka [1.7K]
3 years ago
7

Indicate in standard form the equation of the line passing through the given point and having the given slope. R(4, 0), m = 5

Mathematics
2 answers:
Sergio039 [100]3 years ago
5 0
5x + -1y = 20
You can simplify it to 5x-y=20
adoni [48]3 years ago
3 0

Answer:

5x-y=20

Step-by-step explanation:  

We are asked to find the standard form of the equation of line, which passes through point R(4,0) and having a slope of 5.

First of all, we will write equation of line in point-slope form:

(y-y_1)=m(x-x_1), where,

m=slope of line,

(x_1,y_1) = Coordinates of point that lies on the line.

Upon substituting our given values in point-slope form of equation we will get,

(y-0)=5(x-4)

Now, we will convert our equation into standard form of equation:ax+by=c

Upon using distributive property we will get,

y=5x-20

Now we will subtract 5x from both sides of our equation as:

-5x+y=5x-5x-20

-5x+y=-20

Upon multiplying our equation by -1, we will get,

5x-y=20

Therefore, our required equation would be 5x-y=20.

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Pls pls help <br> Perform the indicated operations.<br> a) 7a/20b<br> b) 7ab/20<br> c) 7/20ab
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Step-by-step explanation:

5( \frac{a + 2}{4b} ) - 2( \frac{a - 1}{10b} ) + 4( \frac{a - 3}{5b} ) \\  \\  \frac{5a + 10 - 2a + 2 + 4a - 12}{20b }  \\  \\  \\  \frac{7a}{20b}

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2 years ago
Please help ASAP IM IN DESPREATE NEED OF HELP
Advocard [28]

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality -y \le -2x-3.  You can make this easier to work with by multiplying through by -1.  Remember to switch the inequality sign when multiplying by a <u>negative</u> number.  OK, you get the inequality

y \ge 2x+3.

The graph will be a half-plane -- all the points on one side of a line.  The line that is the boundary of the half-plane has an equation:  y=2x+3 -- just use an  =  sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form:  y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1).  Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5).  Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality y \ge 2x+3 is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the <u>other</u> side!)

An easy point to pick in this case is the origin, (0, 0).  Put zeros in for x and y in the inequality, and you'll get the statement 0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3.  That's <u>false</u>, so shade the side of the line <u>not</u> containing the origin.  In the image below, the shading is in purple.

All right, now for the other inequality, x+2\le 0.  Subtract 2 from both sides and the inequality becomes x \le -2.  This, too, graphs as a half-plane whose boundary line has equation x=-2.  Graph the line.  A line with an equation that has  x  in it but not  y is a vertical line with all its x-coordinates equal to the number on the right side of the equation.  This line is vertical and goes through points such as (-2, 0).

Pick a point <u>not</u> on the line (the origin works again).  Put the coordinates into the inequality to get 0\le -2 which is <u>false</u>.  Shade the side of the vertical line which does <u>not</u> contain the origin.  In the image below, the shading is in black.

Finally,  YAY!  \o/ ,  the solutions to the system are all the points in the plane that got shaded twice.  In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities x \ge 0 and y \ge 0 in it.  These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis <u>and</u> to the right of the y-axis.

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Olivia is cutting a 1 1/2 m by 3/4 m piece of rectangular paper into two pieces along its diagonal. Find the area
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Answer:

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Step-by-step explanation:

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<em>You need to multiply the length and the width to find an area: </em>

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<em>Now you need to change it into an improper fraction:</em>

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<em>Dividing it by 2:</em>

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