Answer:
By the time Mike left his house at 12:00 noon, Erik had already traveled: 2 x 70 mph =140 miles.
308 - 140 = 168 miles left.
Let the time when they meet =T
70T + 50T =168 miles, solve for T
T =7 / 5 =1.4 hours, or 1 hour and 24 minutes after 12:00 noon.
12 + 1.4 =1 O'clock + 24 minutes, or 24 minutes after 1:00 pm when they will meet.
10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day