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2 years ago

Dana bikes 10 mi in 50 min. At this rate, how far can she bike in 90 min?

Mathematics

2 answers:

lara31 [8.8K]2 years ago

8 0

The answer will be 18 miles

scoray [572]2 years ago

7 0

18 miles in 90 minutes. If you think about it she's going 1 mile every 5 minutes. So if she biked 10 miles in 50 she would have hone 8 miles in 40 minutes. You now simply add 10 miles + 8 miles and you end up with 18 miles.

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For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

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2 years ago

Find the maximum profit and the number of units that must be produced and sold in order to yield the maximum profit. Assume that

V125BC [204]

Answer:

-1.39

Step-by-step explanation:

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we are have to know for which value or input units are these functions at maximum which translates to for how many units is the revenue maximum and for how many same units is our cost minimum.

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So the answer is 32%
Hope this helps!

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ludmilkaskok [199]

1200 is the domain the answer is times the domain

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