All categories

3 years ago

PLEASE HURRY!!!!!!

Mathematics

1 answer:

Anni [7]3 years ago

7 0

Answer:

Step-by-step explanation:

The manager visits a park and interviews people who are waiting to use the tennis courts.

You might be interested in

write a formula that describes the value of an initial investment of $100 that loses value at a rate of 8% per year compounded c

Sati [7]

Answer:

$A = 100(.92)^{t}$

Step-by-step explanation:

5 0

3 years ago

These figures are congruent. What is QR? <br><br> If you put a link I WILL be reporting you!

Westkost [7]

46
I believe this is correct, if not lmk!

5 0

3 years ago

What is the factorization of 84

Vladimir79 [104]

Answer:

2×2×3×7

Step-by-step explanation:

84 is even, so divisible by 2. 84 = 2×42

42 is even, so divisible by 2. 82 = 2×2×21

21 has a sum of digits of 3, so is divisible by 3. 84 = 2×2×3×7

4 0

3 years ago

Point W is located at (0, 7), and point X is located at (4, 0). Julianne wants to find point F on WX such that the ration of WF

aniked [119]

The coordinate of point F will be (1.6,4.2) for the given line segment.

<h3> What is a line segment?</h3>

A line section that can connect two places is referred to as a segment.

In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

Given the F intercept 2 and 3

x = [2(4) + 3(0)]/(2+3)

x = 8/5 = 1.6

Similarly

y = [2(0) + 3 (7)]/(2+3)

y = 21/5 = 4.2

Hence "The coordinate of point F will be (1.6,4.2) for the given line segment".

For more about line segment,

brainly.com/question/25727583

#SPJ1

6 0

2 years ago

Read 2 more answers

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago