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Damm [24]
3 years ago
14

A centralized computer that allows multiple remote users to share the same printing device is referred to as a _________

Computers and Technology
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

central server

Explanation:

This is client-server technology, where the centralized computer with the printing device is playing the role of the central server, and the multiple remote users are the clients. Thus a client-server architecture is established. And this enables remote users to share the same printing device, which is possessed by the central server. Hence, the correct answer here is the central server.

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Write Album's PrintSongsShorterThan() to print all the songs from the album shorter than the value of the parameter songDuration
lidiya [134]

Answer:

kindly check explainations for code

Explanation:

Check below for program code.

#include <iostream>

#include <string>

#include <vector>

using namespace std;

class Song

{

public:

void SetNameAndDuration(string songName, int songDuration)

{

name = songName;

duration = songDuration;

}

void PrintSong() const

{

cout << name << " - " << duration << endl;

}

string GetName() const { return name; }

int GetDuration() const { return duration; }

private:

string name;

int duration;

};

class Album

{

public:

void SetName(string albumName) { name = albumName; }

void InputSongs();

void PrintName() const { cout << name << endl; }

void PrintSongsShorterThan(int songDuration) const;

private:

string name;

vector<Song> albumSongs;

};

void Album::InputSongs()

{

Song currSong;

string currName;

int currDuration;

cin >> currName;

while (currName != "quit")

{

cin >> currDuration;

currSong.SetNameAndDuration(currName, currDuration);

albumSongs.push_back(currSong);

cin >> currName;

}

}

void Album::PrintSongsShorterThan(int songDuration) const

{

unsigned int i;

Song currSong;

cout << "Songs shorter than " << songDuration << " seconds:" << endl;

/* Your code goes here */

for(int i=0; i<albumSongs.size(); i++){

currSong = albumSongs.at(i);

if(currSong.GetDuration()<songDuration){

currSong.PrintSong();

}

}

}

int main()

{

Album musicAlbum;

string albumName;

getline(cin, albumName);

musicAlbum.SetName(albumName);

musicAlbum.InputSongs();

musicAlbum.PrintName();

musicAlbum.PrintSongsShorterThan(210);

return 0;

}

4 0
3 years ago
WHAT DOES THE WORD MONOCHROME MEAN?
Nataly_w [17]
Hi!

A 'Monochrome' is a picture, painting, or drawing in different shades of a single colour.
4 0
3 years ago
(20 points). Some matrixes have very special patterns, for example, in the following matrix, the numbers in the first row are eq
Nostrana [21]

Answer:

#include <iostream>

using namespace std;

void matrix(){

   int row = 5, col = 6;

   int myarr[row][col];

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           if (i == 0){

               myarr[i][x] = (x+1)*(x+1);

          }else if ( x == 0){

               myarr[i][x] = (i+1)*(i+1)*(i+1);

           } else if ( i == x){

                myarr[i][x] = (i+1);

           } else{

                myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];

           }

        }

   }

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           cout<< myarr[i][x] << " ";

       }

       cout<< "\n";

}

}

int main(){

   matrix();

}

Explanation:

The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.

3 0
2 years ago
Part 1 of 4 parts for this set of problems: Given an 4777 byte IP datagram (including IP header and IP data, no options) which i
LekaFEV [45]

Answer:

Fragment 1: size (1332), offset value (0), flag (1)

Fragment 2: size (1332), offset value (164), flag (1)

Fragment 3: size (1332), offset value (328), flag (1)

Fragment 4: size (781), offset value (492), flag (1)

Explanation:

The maximum = 1333 B

the datagram contains a header of 20 bytes and a payload of 8 bits( that is 1 byte)

The data allowed = 1333 - 20 - 1 = 1312 B

The segment also has a header of 20 bytes

the data size = 4777 -20 = 4757 B

Therefore, the total datagram = 4757 / 1312 = 4

6 0
2 years ago
________ are the primary means of authentication for a user's computer and other networks and servers to which the user may have
inn [45]

Answer:

The answer to this question is "Password".

Explanation:

In computer science, any User's computer and networks and server is secured with the password to access all we use the password. for example, if we want to access any WiFi system or any User's computer. Then we will insert the password. If the password is wrong so we can't access the WiFi system or User's computer. similarly, If we want to access any server so we must know about the password. Then we use the server and change it's setting.

So the password is the primary means of authentication for all User's.  

4 0
3 years ago
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