1.4n + 2 = 2n + 3.2
1.4(-2) + 2 = 2(-2) + 3.2
-2.8 + 2 = -4 + 3.2
- 0.8 = - 0.8
Answer:
y=5×+2
Step-by-step explanation:
5(1)+2=7
5(2)+2=12
5(3)+2=17
5(4)+2=22
It
would be: Quadratic -x^2 + 2x - 3. Because if we do x = 3,
![-9+6-3 = -6](https://tex.z-dn.net/?f=-9%2B6-3%20%3D%20-6)
Hope this helped! Brainliest is always appreciated.
Answer:
41.47%
Step-by-step explanation:
618÷(745+618+127)×100
Answer:
![p(x) = (3x^{2} - 8x + 5)(x - 4)](https://tex.z-dn.net/?f=p%28x%29%20%3D%20%283x%5E%7B2%7D%20-%208x%20%2B%205%29%28x%20-%204%29)
Step-by-step explanation:
p(x) has degree 3
(x - 4) has degree 1
So p(x) can be rewritten as a polynomial of degree 2 multiplying (x-4)
So
![p(x) = (ax^{2} + bx + c)(x - 4)](https://tex.z-dn.net/?f=p%28x%29%20%3D%20%28ax%5E%7B2%7D%20%2B%20bx%20%2B%20c%29%28x%20-%204%29)
To find a, b and c, we have to divide p(x) by x - 4.
So
Finding a:
Dividing the first term of p(x) by x - 4.
![\frac{3x^{3}}{x - 4} = 3x^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B3%7D%7D%7Bx%20-%204%7D%20%3D%203x%5E%7B2%7D)
So a = 3.
Now multiplying 3x² by, x - 4, we have:
![3x^{2}(x - 4) = 3x^{3} - 12x^{2}](https://tex.z-dn.net/?f=3x%5E%7B2%7D%28x%20-%204%29%20%3D%203x%5E%7B3%7D%20-%2012x%5E%7B2%7D)
Subtracting p(x) from this:
![3x^{3} - 20x^{2} + 37x - 20 - (3x^{3} - 12x^{2}) = 3x^{3} - 20x^{2} + 37x - 20 - 3x^{3} + 12x^{2} = -8x^{2} + 37x - 20](https://tex.z-dn.net/?f=3x%5E%7B3%7D%20-%2020x%5E%7B2%7D%20%2B%2037x%20-%2020%20-%20%283x%5E%7B3%7D%20-%2012x%5E%7B2%7D%29%20%3D%203x%5E%7B3%7D%20-%2020x%5E%7B2%7D%20%2B%2037x%20-%2020%20-%203x%5E%7B3%7D%20%2B%2012x%5E%7B2%7D%20%3D%20-8x%5E%7B2%7D%20%2B%2037x%20-%2020)
Finding b:
Dividing the first term, after the subtraction, by x - 4.
![\frac{-8x^{2}}{x - 4} = -8x](https://tex.z-dn.net/?f=%5Cfrac%7B-8x%5E%7B2%7D%7D%7Bx%20-%204%7D%20%3D%20-8x)
So b = -8.
Multiplying -8x by x - 4, we have:
![-8x(x-4) = -8x^{2} + 32x](https://tex.z-dn.net/?f=-8x%28x-4%29%20%3D%20-8x%5E%7B2%7D%20%2B%2032x)
Then
Finding c:
![\frac{5x}{x - 4} = 5](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7Bx%20-%204%7D%20%3D%205)
So c = 5.
Just to verify if the remainder is 0.
![5(x - 4) = 5x - 20](https://tex.z-dn.net/?f=5%28x%20-%204%29%20%3D%205x%20-%2020)
![5x - 20 - (5x - 20) = 0](https://tex.z-dn.net/?f=5x%20-%2020%20-%20%285x%20-%2020%29%20%3D%200)
Ok
Then:
![p(x) = (ax^{2} + bx + c)(x - 4)](https://tex.z-dn.net/?f=p%28x%29%20%3D%20%28ax%5E%7B2%7D%20%2B%20bx%20%2B%20c%29%28x%20-%204%29)
![p(x) = (3x^{2} - 8x + 5)(x - 4)](https://tex.z-dn.net/?f=p%28x%29%20%3D%20%283x%5E%7B2%7D%20-%208x%20%2B%205%29%28x%20-%204%29)