The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then





Answer:
The second choice is the correct one.
Step-by-step explanation:
20x^4 - 45x^2
GCF is 5x^2, so the factors are:
5x^2( 4x^2 - 9)
Now 4x^2 - 9 is the differencr of 2 squares:
4x^2 - 9 = (2x + 3)(2x - 3)>
Answer:
The price of hot dog is $2.5 and that of a pretzel is $1.25.
Step-by-step explanation:
Let the cost of hotdogs be x and that of pretzels be x.
So,
4x+3y = 13.75 ...(1)
and
2x+5y = 11.25 ...(2)
Multiply equation (2) by 2.
4x+10y = 22.5 ...(3)
Subtract equation (1) from (3).
4x+10y-(4x+3y) = 22.5-13.75
4x+10y-4x-3y = 8.75
7y = 8.75
y = 1.25
Put the value of y in equation (1).
4x+3(1.25) = 13.75
4x+3.75 = 13.75
4x = 13.75-3.75
4x = 10
x = 2.5
So, the price of hot dog is $2.5 and that of a pretzel is $1.25.
You can also approach it this way:
28 flowers times n = 3444
so n = 123
11 x 123 = roses, 17 x 123 = tulips.
Those 2 products should add up to 3444. They do. :-)
gotchaaaaaa
ahhh
thanxxx