Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
Answer:6x^3+16x^2-42x-40
Step-by-step explanation:
To expand
(-2x-8)(-3x^2+4x+5)
6x^3-8x^2-10x+24x^2-32x-40
Collect like terms
6x^3-8x^2+24x^2-10x-32x-40
6x^3+16x^2-42x-40
Answer:
(-3,-8)
Step-by-step explanation:
okay so what we can do here is elimination
we can do this first by multiplying the entire second equation by 2
so then it would become
2(5x-2y=1)
10x-4y=2
now we can add the two equations together which will eliminate y
so
-8x+4y=-8 plus
10x-4y=2 equals
2x=-6
we did that by combining like terms
next we can simplify that
x=-3
now we can plug that into the equation
-8(-3)+4y=-8
simplify
24+4y=-8
4y=-32
y=-8
our answer would be
(-3,-8)
Answer:
x = 0
Step-by-step explanation:
If you do the equation y2 - y1 over x2 - x1 you get 0 and the x intercept is 5 y=0×5 = 0
Answer:
negative - $9.50
Step-by-step explanation:
