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3 years ago

Will give Brainliest! if right!

Mathematics

2 answers:

puteri [66]3 years ago

6 0

Class A
mean = (2 + 4+ 6 + 14 + 22)/5 = 48/5 = 9.6
median = 6

class B
mean = (10 + 12+ 14 + 16 + 22)/5 = 74/5 = 14.8
median = 14

answer is Class B

higher mean and median

grin007 [14]3 years ago

3 0

Class B has more attendance for class

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Answer..........please

Marina86 [1]

Answer: 2.5

Step-by-step explanation:

I believe 2.5 because If we take y/x we have 4,10 so I divide.

7 0

2 years ago

Read 2 more answers

A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those date

Anni [7]

Answer:

Confidence interval variance [21.297 ; 64.493]

Confidence interval standard deviation;

4.615, 8.031

Step-by-step explanation:

Given :

Variance, s² = 34.34

Standard deviation, s = 5.86

Sample size, n = 27

Degree of freedom, df = 27 - 1 = 26

Using the relation for the confidence interval :

[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]

From the chi distribition table :

X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844

Hence,

[34.34*26 / 41.923] ; [34.34*26 / 13.844]

[21.297 ; 64.493]

The 95% confidence interval for the population variance is :

21.297 < σ² < 64.493

Standard deviation is the square root of variance, hence,

The 95% confidence interval for the population standard deviation is :

4.615 < σ < 8.031

3 0

2 years ago

If f(x) =3^x+10 and g(x) =4x -2 find (f+g)(x)

Valentin [98]

Answer:

$(f+g)(x)=3^x+4x+8$

if $f(x)=3^x+10$ and $g(x)=4x-2$ .

Step-by-step explanation:

We are given $f(x)=3^x+10$ and $g(x)=4x-2$ .

We are asked to find $(f+g)(x)$ .

$(f+g)(x)$ means $f(x)+g(x)$

$(f+g)(x)=(3^x+10)+(4x-2)$

You only have one pair of like terms, that is the constants.

$(f+g)(x)=3^x+4x+10-2$

$(f+g)(x)=3^x+4x+8$

7 0

2 years ago

Read 2 more answers

Use identities to find the values of the sine and cosine functions for the following angle measure.

puteri [66]

Using the cosine double angle formula,

$\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}$